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Mookie Betts wins 2018 American League MVP

What a year for Mookie Betts.

Oct 24, 2018; Boston, MA, USA; Boston Red Sox outfielder Mookie Betts (left) reacts after scoring a run against the Los Angeles Dodgers in the fifth inning in game two of the 2018 World Series at Fenway Park. Mandatory Credit: Bob DeChiara-USA TODAY Sports

The offseason of hardware has continued for Red Sox outfielder and 2018 World Series champion Mookie Betts.

With the greatest individual honor Betts could have taken home, too, as the 2018 American League's Most Valuable Player.

In Betts' fourth full season in the Majors, he led baseball with a .346 batting average, 129 runs and a .640 slugging percentage, and hammered 47 doubles and 32 home runs. Betts was also a demon on the basepaths, with 30 stolen bases. Betts also led the lead in WAR (wins above replacement), and had the highest WAR for any MVP since Barry Bonds in 2002.

Betts is also in historically good company, too, as he became the first American League talent to win the World Series, as well as MVP, Gold Glove, and Silver Slugger honors all in the same season.

Red Sox manager Alex Cora, meanwhile, took to Twitter to congratulate Betts.

The honor makes Betts the first Red Sox player to win the A.L. MVP since Dustin Pedroia in 2008.

Ty Anderson is 98.5 The Sports Hub’s friendly neighborhood straight-edge kid. Ty has been covering the Bruins (and other Boston teams) since 2010, has been a member of the PHWA since 2013, and went left to right across your radio dial and joined The Sports Hub in 2018. Ty also writes about all New England sports from Patriots football to the Boston Celtics and Boston Red Sox.